9x^2-24x-25=0

Solution for 9x^2-24x-25=0 equation:

9x^2-24x-25=0

a = 9; b = -24; c = -25;
Δ = b2-4ac
Δ = -242-4·9·(-25)
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-6\sqrt{41}}{2*9}=\frac{24-6\sqrt{41}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+6\sqrt{41}}{2*9}=\frac{24+6\sqrt{41}}{18}
$